The Quest for 700: Weekly GMAT Challenge (Answer)
July 24th, 2008 | Posted in Blogroll
Yesterday, Integrated Learning posted a 700 level GMAT question on our blog. Today, they follow-up with the answer:
In this problem, we are asked for the minimum value of wxyz, meaning that we need to find the minimum value of n. We know that n is divisible by both 7,425 and 4,235, and the minimum n would be the Lowest Common Multiple of those two numbers. The best way to figure out lowest common multiple is to break numbers down to their prime factors and choose the appropriate number of prime numbers from each.
7,425 = 3 x 3 x 3 x 5 x 5 x 11
4,235 = 5 x 7 x 11 x 11
The lowest common multiple would have to be 3 x 3 x 3 x 5 x 5 x7 x 11 x 11, or 325272112. From this we see that
w = 3
x = 2
y = 1
z = 2
So wxyz = 3(2)(1)(2) = 12.
Integrated Learning provides professional, experienced GMAT tutors throughout the United States.
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